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x^2-2.4x-3.6=0
a = 1; b = -2.4; c = -3.6;
Δ = b2-4ac
Δ = -2.42-4·1·(-3.6)
Δ = 20.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{20.16}}{2*1}=\frac{2.4-\sqrt{20.16}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{20.16}}{2*1}=\frac{2.4+\sqrt{20.16}}{2} $
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